Aglobe has a diameter of 18 in. what is the surface area of the globe to the nearest square inch?
a. 108 in2
c. 1,018 in2
b. 285 in2
d. 2,216 in2

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐