In which quadrant is θ located if cscθ is negative and tanθ is positive?

is located in 3rd Quadrant.

Step-by-step explanation:

We are given that  is negative  and  is positive

We have to find Quadrant in which is located.

We have 4 Quadrants.

In 1st Quadrant , All trigonometric ratios are positive.

In 2st Quadrant , sin and cosec are positive while others are negative.

In 3rd Quadrant , tan and cot are positive while others are negative.

In 4th Quadrant , cos and sec are positive while others are negative.

Therefore, According to given information located in 3rd Quadrant.

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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