Given the number 456789abh, list out its byte value in little-endian order

The given 32-bit value is 456789ab in hexadecimal notation.
Each byte uses two hex digits. 
The 4 bytes contained in the number are
45 67 89 ab.

Little-endian order stores the least significant bytes first in the smallest memory address.
Therefore the storage in little-endian order is
ab
89
67
45

 
The byte values are ab, 89, 67, 45

The answer should be c.