Aset of test scores is normally distributed with a mean of 70 and a standard deviation of 10. in what percentile is a score of 65?

To answer this question, first calculate the z-score:
        test score - mean score           65 - 70
z = = = -5/10 = -0.5
                   std. dev.                              10

We need to determine the area under the normal curve to the left of z = -0.5.
Refer to a table of z-scores, and look for z=-0.5.  What area appears in connection with this z-score?  It's less than 0.5000.

Using my TI-83 Plus calculator (specifically, its "normalcdf( " function, I found that the area under the std. normal curve to the left of z = -0.5 is 0.309.

Thus, the percentile is 30.9, or roughly 31 (31st percentile).

Roughly 31% of students earned a grade lower than 65, and roughly 69% earned a higher grade.

The slope of the function is 0.5.