Ms. rao buys a computer, a printer, and a scanner for $2,543. the computer costs $1,502 more than the printer. the printer costs $123 more than the scanner. how much does ms. rao pay for the computer? how did you get the answer? i got the answer of $1808.

Ms. Rao Pays $1890 for the computer Price of Computer(C) + Printer(P) + Scanner (S) = $2543 Price of Computer: C = 1502 + P Price of Printer: P = 123 + S So Price of computer now becomes: C = 1502 + 123 + S (Here we replace P with 123 + S) It is Algebra from here: C + P + S = 2543 (1502 + 123 + S) + (123 + S) + S = 2543 1748 + 3S = 2543 3S = 2543-1748 3S = 795 S = 795/3 S = 265 C = 1502 + 123 + S C = 1502 + 123 + 265 C = $1890 Ms. Rao pays $1890 for the computer

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12