If two sides of a triangle measure 12 and 7, which  cannot be the perimeter of the triangle

Hello Tovarmackenzie!
We can utilize the Triangle Inequality Theorem, Which states

A + B > C
A + C > B
B + C > A

With that said, we are going look for C.
We know that
12 + 7 > C
So
19 > C
OR
C < 19
So our 3rd leg has to be less than 19.

So if we make C  =18.999 and Sum up all the sides, 12 + 7 + 18.999 = 37.999
this means the max perimeter is 37.999.. so we know  D: 38 cannot be the perimeter.

A

if 12 is the longest and 7 is the shortest then that would mean the addition of another 7 would be 28, no matter the triangle it is impossible for the perimeter to equal 29

than do 23.50 times 18 and then divide your answer by 100 than you will get x.