What is the equation of a line that passes through the point (9, −3) and is parallel to the line whose equation is 2x−3y=6 ? enter your answer in the box

The equation of the line, in slope-intercept form, that is parallel to 2x - 3y = 6 and passes through (9, -3) is:

Given:

Points the line passes through, (9, -3)

The equation of the line it is parallel to: 2x - 3y = 6

Note:

Parallel lines have the same slope valueEquation of a line in slope-intercept form is: y = mx + b. (m is slope; b is y-intercept)Point-slope form is; y - b = m(x - a)

First, rewrite 2x - 3y = 6 in slope-intercept form to determine its slope.

The slope of 2x - 3y = 6 is therefore 2/3.

Thus, the slope of the line that passes through (9, -3) is also 2/3.

Write the equation of the line in point-slope form:

Substitute m = 2/3, and (a, b) = (9, -3) into y - b = m(x - a)

Thus:

Rewrite in slope-intercept form

Therefore, the equation of the line, in slope-intercept form, that is parallel to 2x - 3y = 6 and passes through (9, -3) is:

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2x - 3y = 6
-3y = -2x + 6
y = 2/3x - 2the slope here is 2/3. A parallel line will have the same slope

y = mx + b
slope(m) = 2/3
(9,-3)...x = 9 and y = -3
now we sub and find b, the y int
-3 = 2/3(9) + b
-3 = 6 + b
-3 - 6 = b
-9 = b

so ur parallel equation is : y = 2/3x - 9 <== or 2x -3y = 27

the image of (6, 9) under a dilation is (4, 6). the scale factor is

b. 2/3

The answer might be a