9. suppose a new groundskeeper decides that he has enough chalk to line 600 feet of the perimeter of the field. what is the maximum area of the field this chalk could outline, assuming the length remains 30 yards longer than the width?

Perimeter = 2(L+W) Area = L * W 1 yard = 3 foot This implies that the length is (30 * 3) 90 feet longer than the width Therefore L = W + 90 So Perimeter = 2(W+90 + W) = 600 = 4W + 180 Therefore W = 420/4 = 105 L = 105 + 90 = 195 Area = 195 * 105 = 20,475 Square feet Hence the Maximum area of the field the chalk could outline is 20,475 Square feet