The function f(x)=40,000(0.75)x represents the number of bacteria present in a petri dish after x hours. what is the average rate of change in the number of bacteria between hour 2 and hour 5? question 1 options: a.−6102 bacteria/h b.4336 bacteria/h c.−4336 bacteria/h d.6102 bacteria/h

Important:  f(x)=40,000(0.75)x   should be written  f(x)=40,000(0.75)^x.
                                                          f(b) - f(a)
The average rate of change (arc) is
                                                             b - a

Here that comes to 40000 [0.75^5 - 0.75^2]
                               
                                            5-2

or    arc = -13007.81 / 3  = -4335.9 bacteria per year.

The total would be 40.53