Write an equation of the line passing through the point a(2, 0) that is parallel to the line y = 3x−5 .

Hello,

In order for lines to be parallel to each other, they need to have the same slope. So, let's plug in the points and slope for point-slope form.

The equation for point-slope form is: y-y1 = m (x-x1)

Let's plug in the points into the equation. 
y-5 = m (x-0), and then let's plug in the slope for "m" : y-5 = 3 (x-0).

After plugging the numbers in, the equation is simplified to y-5 = 3 (x-0). Then distribute the 3 to the parenthesis. y-5 = 3x. To get y by itself, you need to add 5 to both sides. After that, the equation parallel to that equation is: y = 3x + 5.

Hope this helps! =)

(x) - (y) = (1 + 4i)

(3 + 6i) - (2 + 2i) = (1 + 4i)