An ontario resident has a choice of drug plans. plan a cost $500 a year, plus $10 for each prescription plan b cost $650 a year. the person wanted to know how many prescriptions could be purchased before the $650 plan became the better deal. write an equation to represent this relationship. solve the equation to determine the number of prescriptions that makes the two plans equal.

Hello there!

a. Okay, we can set up the equation like this: 500 + 10p = 650.

b. First, let’s subtract 500 from both sides. When we do, we get 10p = 150. Divide each side by 10 to isolate the “p”. When we do, we get p = 15. It would take 15 prescriptions to make both plans equal.

c. With that being said, add 1 more prescription to get 16. It would take 16 prescriptions for the $650 plan to be a better deal.

Use a calculator basically

Answer: b 2 = 1.

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

therefore, b 2= 1.