Factor the expression. x^4+6x^2-7 completely. show work!

Hi there!

Let's let y = x^2
Substitute y into the equation
y^2 + 6y - 7
Now, we need two factors of -7 that add up to 6
-1 and 7 should work
Now, factor
(y - 1)(y + 7)
Substitute y=x^2 back into the equation
(x^2 - 1)(x^2 + 7)

Edit: Garydesir1 made an important note. (x^2 - 1) can be factorized into (x+1)(x-1)
Your full factorization is (x-1)(x+1)(x^2 + 7)

Have an awesome day! :)

Hello there!

The answer is: (x + 1)(x -1)(x² + 7)



Well, I am not sure how to explain this. But what you need to realize is that you have x^4. It means that you gonna need two x in the left and one x^2 on the right side.

I hope this help!