Question follows the 5th term of an exponential sequence is greater than the 4th term by thirteen and half and the 4th term is greater than the 3rd term by 9 .find the common ratio and the 1st term

I figured it out but was thrown off by the poor wording used. Please always copy the question exactly how it is given to you otherwise you might not get any help or wrong answer.

terms of geometric sequence
A(n) = ar^(n-1)
where "a" represents first term
here you are given information to set up two equations in two variables "a" and "r". you must combine equations to solve for one variable at a time.

A(4) - A(3) = 9
(ar^3) - ar^2 = 9
a(r^3/2 - r^2) = 9
a = 9/(r^3-r^2)

A(5) - A(4) = 13.5
ar^4 - ar^3 = 13.5
a(r^4 - r^3) = 13.5

combined
9/(r^3 - r^2) * (r^4 - r^3) = 13.5
cross multiply
9r^4 - 9r^3 = 13.5r^3 - 13.5r^2
combine like terms
9r^4 - 22.5r^3 + 13.5r^2 = 0
factor/polysolver
r = 3/2 or r = 1
but r cannot equal 1

ratio is 3/2 = 1.5

a = 9/(1.5^3 - 1.5^2) = 8
first term is 8

Idon’t understand sorry

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)