Ye has his own business. he checks his sales receipts three times a day. one day, his afternoon sales eere $50 more than his morning sales, and his evening sales were three times his afternoon sales. if his total slaes for the day were $1,000, what were his evening sales?

Hence, his evening sales were $630.

Step-by-step explanation:

Let the sales in the morning be 'x'

Let the sales in afternoon be x+50

Let the sales in the evening be 3(x+50).

Total sales for the day = $1000

According to question, it becomes

So, his evening sales would be

Hence, his evening sales were $630.

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

idk

step-by-step explanation: