City a and city b had two different temperatures on a particular day. on that day, four times the temperature of city a was 8° c more than 3 times the temperature of city b. the temperature of city a minus twice the temperature of city b was −3° c. what was the temperature of city a and city b on that day? your city a was 5° c, and city b was 4° c. city a was 3° c, and city b was −1° c. city a was 8° c, and city b was −3° c. city a was 5° c, and city b was −5° c.

City A = x

City B = y

1st equation: 4x-8 =3y

 2nd equation: x-2y = -3 , rewrite as x = 2y-3

replace x in eq. 1 with equation 2

4(2y-3) -8 =3y

8y-12-8=3y

8y-20 = 3y

-20 = -5y

y = -20/-5 = 4

x = 2y-3 = 2(4)-3 = 5

City A was 5° C, and City B was 4° C. 

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.