Find three consecutive even integers such that the sum of twice the smallest number and three times the largest is 42.

Let x be the first 
the second x +2 
the third x+ 4

twice the smallest  2x

three times the largest  3(x+4 )
 
2x + 3(x+4 )=42

2x +3x +12 = 42

5x= 30

x=6        the second is 8   the third is 10

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12

+1,000)=g7e=mc2-g=7 because if you know algebra you should know g=7 to get your answer