It takes 40 min for a bus to travel the 36 miles from framingham to worcester. a car traveling from worcester to framingham moves 1.5 times as fast as the bus. if the car and the bus start moving towards each other simultaneously, after how many minutes will they meet?

The velocity of the bus is:

velocity (bus) = 36 miles / 40 min

velocity (bus) = 0.9 miles / min

Since the car is 1.5 times faster, so the velocity of the car is:

velocity (car) = 1.5 * 0.9 miles / min

velocity (car) = 1.35 miles / min

At the meeting point, the sum of the distance is equal to 36 miles. Therefore:

1.35 t + 0.9 t = 36

2.25 t = 36

t = 16 min

So they will meet after 16 minutes.

i don't have the answer rn but go to math papa. it shows the steps and the answer. hope this : )

step-by-step explanation:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180