13+8me ! due today ! complete the coordinate proof of the theorem. enter your answers in the boxes. the coordinates of parallelogram abcd are a(0, 0) , b(a, 0) , and d(c, b) . the coordinates of the midpoint of ac¯¯¯¯¯ are (, b2 ). the coordinates of the midpoint of bd¯¯¯¯¯ are ( a+c2 , ). the midpoints of the diagonals have the same coordinates. therefore, ac¯¯¯¯¯ and bd¯¯¯¯¯ bisect each other.

Step-by-step explanation:

1). Coordinates of point C will be

x - coordinates = [Distance of B from the origin + Distance of D from y axis]

                         = (a + c)

y - coordinates = (Distance of D from x - axis)

                         = b

Therefore, coordinates of C will be [(a + c), b]

2). Coordinates of the midpoint of AC =

=

[Since coordinates of the midpoint of (x, y) and (x', y') are denoted by ()]

3). Coordinates of the midpoint of BD =  

=

my dear correct answer is option number 3