Arectangle is 4 cm longer than it is wide, and its area is 117 cm2 . find its dimensions.

The area of a rectangle is equal  L x  W   

4 cm longer than it is wide   L = 4 + W

L x  W = 117     we replace L here 

(4 + W ) x W = 117 

4W + W ^2  = 117 

4W + W ^2  -117 = 0
W ^2 +4 W -117 = 0

W² + 4W - 117 = 0


THEN u want to use the use the quadratic formula
 

OR Factoring gives us

(W + 13)(W - 9) = 0

W = -13 or 9

But it can't be negative, so

W = 9  and L= 9+4 = 13

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