An acorn falls from the branch of a tree to the ground 25 feet below. the distance, s, that the acorn is from the ground as it falls is represented by the equation s(t) = –16t^2 + 25, where t is the number of seconds. for which interval of time is the acorn moving through the air?

The acorn was moving through the air in the time interval of to .

The given distance equation covered by acorn while falling from the tree is given as   which is time dependent.

Factorise the given equation by equating the given equation to zero,

Hence, taking as the starting of fall, the acorn was moving through the air in the time interval of to .

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step-by-step explanation:

this is not possible to solve with the info given.   you need at least an one angle somewhere.

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.