Ineed with this, 10 points + brainliest answer 9. solve the system by substitution. {-x – y – z = -8 {-4 + 4y + 5z = 7 {2x + 2z = 4

Solve for y in −4+4y+5z=7

Substitute y=\frac{11-5z}{4}y=​4​​11−5z​​ into -x-y-z=-8−x−y−z=−8
−x−​4​​\frac{11−5z}{4}​​−z=−8

Substitute y=\frac{11-5z}{4}y=​4​​11−5z​​ into 2x+2z=42x+2z=4
2x+2z=4
Solve for x in -x-\frac{11-5z}{4}-z=-8−x−​4​​11−5z​​−z=−8
x=−​4​​\frac{11−5z}{4}​​+8−z

Substitute x=-\frac{11-5z}{4}+8-zx=−​4​​\frac{11−5z}{4}​​+8−z into y=\frac{11-5z}{4}y=​4​​
y=​4​​ \frac{11−5z}
​​Substitute x=-\frac{11-5z}{4}+8-zx=−​4​​ \frac{11−5z}{4}​​+8−z into 2x+2z=42x+2z=4
​\frac{5z−11​​}{2}+16=4

Solve for z in \frac{5z-11}{2}+16=4​2​​5z−11​​+16=4

z=\frac{-13}{-5}

Substitute z=-\frac{13}{5}z=−​5​​13​​ into x=-\frac{11-5z}{4}+8-zx=−​4​​11−5z​​+8−z

x=\frac{23}{5}

Substitute z=-\frac{13}{5}z=−​5​​13​​ into y=\frac{11-5z}{4}y=​4​​11−5z​​

y=6
​​

y=6