On this map, oxford street is perpendicular to , and rosewood street is perpendicular to . assume that the street intersections form right angles.

Part a) Oxford Street is perpendicular to Waterloo St and Rosewood St

Part b) Rosewood Street is perpendicular to Oxford St and George St

Step-by-step explanation:

we know that

If the street intersections form right angles

then

the street intersections are perpendicular

so

Part a) Oxford Street is perpendicular to Waterloo St and Rosewood St

Part b) Rosewood Street is perpendicular to Oxford St and George St

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