The right triangle shown has one leg of length 5 centimeters and a hypotenuse of length 13 centimeters a) find the length of the other leg b) what is the perimeter of the triangle c) what is the area of the triangle

A) By Pythagoras' Theorem  x^2 = 13^2 - 5^2    where x = length of the other leg.  x^2 = 169 - 25 = 144 so x = 12. cms.

b) perimeter = 5 + 12 + 13 = 30 cms

c) Area of triangle = product of the 2 legs  = 5*12 = 60 cm^2.