Find the probability that when 200 reservations are accepted for united flight 15, there are more passengers than seats available

The solution for this problem is:

We know the problem has the following given:

Sample size of 200

X = 182

And the probability of .9005; computation: 1 - .0995 = .9005

So in order to get the probability:

P (x >= 182) = 1 – 0.707134 = .292866 is the probability that when 200 reservations 
are recognized, there are more passengers showing up than there 
are seats vacant.

The other solution is:

p (>= 182) = p(183) + P(184) + P(185) + ... + P(199) + P(200) = 0.292866

answer: 20

step-by-step explanation: subtract the minimum date value from the maximum data value to find the date range. in this casem the date range is 42 - 22 = 20

hope this ! : ) ~zane

its line 2 i just added the rest or else it wouldn't let me answer