The sum of two consecutive even integers is 22 less than four times the smallest of the two numbers. find the larger of the two integers

Let the two consecutive even numbers be 'A' and 'B' (A being the lesser and B the larger)

Based on the question, A + B = 4A - 22  (1) 
since B is a consecutive even number to A, then  B = A + 2  (2)

By substituting (2) into (1),
   A + (A + 2) = 4A - 22
   2A + 2 = 4A - 22
   2 + 22 = 2A
            A = 12

Now, if A = 12,
   then B = 14

∴ the two integers are 12 and 14. 
 

Agc and bgd are vertical angles