Mathematics, 18.07.2019 10:00 rose782751

Hoover dam on the colorado river is the highest dam in the united states at 221 m, with an output of 1300 mw. the dam generates electricity with water taken from a depth of 150 m and an average flow rate of 650m3/s. (a) calculate the power in this flow. (b) what is the ratio of this power to the facility's average of 680 mw?

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Answer from: tus

The power is $9.56\times 10^8 \ watt$ in this flow.

The ratio of this power to the facility's average of 680mw is 4.05.

Given that,

Hoover Dam on the Colorado River is the highest dam in the united states at 221 m, with an output of 1300 MW.

The dam generates electricity with water taken from a depth of 150m and an average flow rate of 650m3/s.

We have to determine,

Calculate the power of the river in this flow.

What is the ratio of this power to the facility's average of 680 MW?

According to the question,

To find the power of the follow firstly calculate the value of the power then evaluate the value of the power by using the formula given below.

$Pressure = h\times p \times g \\\\Pressure = 150 \times 1000 \times 9.81\\\\Pressure = 1,471,500$

Then,

The value of the power is determined by the formula;

$Power \ flow = 1471500 \times 650 \\\\Power flow = 956,475,000\\\\Power flow = 9.56 \times 10^8 \ watt$

The ratio of this power to the facility's average of 680 mw is determined by = power flow ÷ average power.

The ratio of this power to the facility's average = $\dfrac{9.56\times 10^8}{680}$

The ratio of this power to the facility's average = $0.0452\times 10^2$

The ratio of this power to the facility's average = 4.05

To know more about the Ratio click the link given below.

link

Answer from: martinezkimberly706

Height (h)= 150 m, 650 m3 /s.
150 m, average flow rate = 650 m3 /s.
Power = force x velocity, velocity = flow rate /area.
Power flow= force x flow rate /area.Pressure = force / areaPower flow= pressure x flow rateNow,
a) Pressure = h ρ g
Pressure = 150 m * 1000 kg/m3 * 9.81 m/s^2
Pressure = 1471500 Nm^2
=> Power flow= 1471500 Nm^2 * 650 =956475000 W = 9.56 ×10^8 W

b)Ratio of this power to the facility = Power flow / average power
b)Ratio of this power to the facility = Power flow / average power
Ratio of this power to the facility = 9.56 × 10^8 W / 680 MWRatio of this power to the facility = 0.0405 ×10^2
Ratio of this power to the facility = 1.405

Answer from: Quest

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's

Answer from: Quest

ghjmutmum

step-by-step explanation:

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