Use substitution to solve the system. x-2y=-8 4x-3y=-17 x= y=

This is what you do.

x - 2y = -8
4x - 3y = -17
Add 2y to both sides on the first equation.
x = 2y - 8
4x - 3y = -17
Now substitute the x value.
4(2y - 8) -3y = -17
8y - 32 - 3y = -17
Combine like terms
5y - 32 = 17
Add 32 to both sides.
5y = 15
Divide.
y = 3
Now find x by plugging in 3 into 1 equation.
x - 2(3) = -8
x -6 = -8
Add 6 to both sides.
x = -2
So you solution is (-2, 3).
I hope this helps love! :)

All points to the left of zero on a horizontal number line are negative. a number line is a picture of a graduated straight line that serves as abstraction for real numbers. this number line can be extended to the left to represent numbers which are smaller than 0. such numbers are called negative numbersmark me brainliest