The equation of line m is 3x−5y=−4. what is the slope of a line that is perpendicular to line m? enter your answer in the box.

First, write your equation in slope-intercept form, or form y = mx + b:
1) Solve for 5y:
3x - 5y = -4
3x + 4 = 5y
2) Divide everything by 5:
y = 3x/5 + 4/5
Now, we got it.
In this line slope is 3/5 because it is multiplier for x, and, the rule is that
m * p = -1
where m is the slope of the line, and p is the slope of the line perpendicular to this.
3) Now, solve there for p by plugging in value for m:
p = -1/m
p = -1 / (3/5) = -5/3
4) Now just write the equation in this form: y = px + b:
y = -5x/3 + b
This is the equation of the line perpendicular to the given one. Hope this helps!

The correct graph is the second one, with the points being at (-6,0), (2,0) and reaching down to (-2,-8)