Which of the following show the factored equivalent of f(x) = (x2 - 81)(x + 5) and its zeroes. f(x) = (x - 6)(x + 6)(x + 5); x= 6, -6, -5 f(x) = (x - 9)(x + 9)(x + 5); x= 9, -9, -5 f(x) = (x - 9)(x + 9)(x + 5); x= -9, -9, -5 f(x) = (x - 6)(x + 6)(x + 5); x= -6, 6, -5

Option B

Step-by-step explanation:

We have to write the function f(x) in the factored form.

f(x) = ( x² - 81 ) ( x+5 )

Since [ a² - b² = ( a-b ) ( a+b) ]

so f(x) = ( x² - 9² ) ( x + 5 )

=  ( x - 9 ) ( x + 9 ) ( x + 5 )

If these factors are the zero factors then

( x - 9 ) = 0 ⇒ x = 9

( x + 9 ) = 0 ⇒ x = -9

x + 5 = 0 ⇒ x = -5

Option B will be the answer.

i do not know this sorry : (

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2