Complete the coordinate proof of the theorem. given: a b c d is a parallelogram. prove: the diagonals of a b c d bisect each other. enter your answers in the boxes. the coordinates of parallelogram abcd are a(0, 0) , b(a, 0) , c( , ), and d(c, b) . the coordinates of the midpoint of ac¯¯¯¯¯ are ( , b2 ). the coordinates of the midpoint of bd¯¯¯¯¯ are ( a+c2 , ). the midpoints of the diagonals have the same coordinates. therefore, ac¯¯¯¯¯ and bd¯¯¯¯¯ bisect each other.

The coordinates of parallelogram ABCD are A(0, 0) , B(a, 0) , C(a+c, b), and D(c, b)

The coordinates of the midpoint of AC are ((a+c)/2, b/2)

The coordinates of the midpoint of BD are ((a+c)/2, b/2)

Step-by-step explanation:

The x-coordinate of C is the addition of x-coordinates of D and B

The y-coordinate of C is the same as y-coordinates of D

The x-coordinate of the midpoint of AC are half of the distance in x-coordinate between A and C, that is, (a+c)/2

The y-coordinate of the midpoint of DB are half of the distance in y-coordinate between D and B, that is, b/2

so a parallelogram is just like a square base times height. multiply 40 and 39 to get 1560 inches.

a triangle is base times height divided by two. so multiply 7.9 and 5 and then divide it by 2 to get 19.75inches.

the kite can be split into two separate triangles and added together to get the total area. 30 x 4 /2 which equals 60. make sure to double it for the two triangles making 120.

c

step-by-step explanation: