Find 3 consecutive even integers if their sum decreased by 10 equals -22

Three consecutive even integers can be represented by x, (x+2), and (x+4).

(x + (x + 2) + (x + 4)) - 10 = -22   Get rid of the parentheses
    x + x + 2 + x + 4 - 10 = -22   Combine like terms (x + x + x) and (2 + 4 - 10)
                               3x - 4 = -22   Add 4 to both sides
                                    3x = -18   Divide
                                      x = -6
Check you work.

x = -6
x + 2 = -4
x + 4 = -2

(-6 - 4 - 2) - 10 = 22
-12 - 10 = -22

So, your three integers are -6, -4, and -2 .

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