Which of the following represents the zeros of the function g(x) = x3 - 9x2 + 2x + 48 ? a. x= -8, x= 2 , and x= -3 b. x = 8, x = -2 , and x = 3 c. x = 6, x = -4 , and x = 9 d. x = -6, x = 4 , and x = -9

g(x) = x^3 - 9x^2 + 2x + 48 ?

Probe some roots. When you use x = - 2

you will have: (-2)^3 - 9(-2)^2 + 2(-2) + 48 = -8 - 36 - 4 + 48 = 0

So, - 2 is a root

From that you can divide x^3 - 9x^2 + 2x + 48 by x + 2 and you will get

x^2 - 11x + 24

Then you can factor that: (x - 8)(x - 3)

So, the three roots are x = - 2, x = 3 and x = 8, which is the option B.

option B. x = 8, x = -2 , and x = 3
 

Are you asking for 6 or 15?