The units digit of a perfect square is 6. what are the possible values of the tens digit?

If is a perfect square ends in 6,  the last digit squared must end in 6 as well.

The only single digit numbers squared that end in 6 are:    4*4=16   and   6*6=36  

They are the only 2 so the number that is being squared must end in 4 or 6

Let the second last digit be X.  X can be any digit.

So the last 2 digits of our number that is being squared are either   X6   or    X4

That is, the last 2 digits of the number are either (10X+6)   or   (10X+4),

this will result in X always being an odd number.

don't report but were is the digram

step-by-step explanation:

really really sorry if i'm

-12 -5(x + 4) = 3x

-12 - 5x - 20 = 3x

-12 - 20 - 5x = 3x

-32 - 5x = 3x

    + 5x   + 5x

-32 = 8x

8         8

- 4= x