The area of a rectangle is 3535 square meter. the width is 2525 meter. a. what is the length of the rectangle? write your answer as a fraction in simplest form. the length of the rectangle is meters. b. how many times greater is the length than the width? write your answer in simplest form. the length is times greater than the width.

a. The formula for the area of rectangle is:

A = l w

so given that A = 3/5 m^2 and w = 2/5 m,

l = A / w

l = (3/5 m^2) / (2/5 m)

l = 3/2 m or 1.5 m

b. We take the ratio l/w:

l/w = (3/2 m) / (2/5 m)

l/w = 3.75

So the length is 3.75 times greater than width

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w

he kicked it up? is this the answer ?

step-by-step explanation: