Write the point-slope form of the line that passes through (6, 1) and is perpendicular to a line with a slope of -3. include all of your work in your final answer.

Perpendicular to a line with a slope of -3. A perpendicular line will have a negative reciprocal slope. All that means is " flip " the slope and change the sign. So we have a slope of -3 (or -3/1)flip it, making it -1/3change the sign, making it 1/3. So our perpendicular line will have a slope of 1/3.

y = mx + b
slope(m) = 1/3
(6,1)x = 6 and y = 1
now we sub into the formula and find b, the y int
1 = 1/3(6) + b
1 = 2 + b
1 - 2 = b
-1 = b

so ur perpendicular equation is : y = 1/3x - 1 <==