Mathematics, 20.07.2019 18:30 DissTrack

Which of the following statements are never true? select all that apply. three points are coplanar two planes meet in exactly one point opposite rays form a line two lines that lie in a parallel planes are parallel two lines meet at exactly two points

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Intersecting lines are ? coplanar.AlwaysTwo planes ? intersect in exactly one pointNeverThree points are ? coplanar.AlwaysA plane containing two points of a line ? contains the entire line.AlwaysFour points are ? coplanar.SometimesTwo lines ? meet in more than one point.NeverTwo parallel lines are ? coplanar.AlwaysTwo skew lines are ? coplanar.NeverTwo opposite rays ? form a line.AlwaysLine TQ and QT are ? the same line.AlwaysRay GH and HG are ? the same ray.NeverRay JK and JL are ? the same ray.SometimesTwo planes that do not intersect are ? parallel.AlwaysTwo lines that lie in parallel planes are ? parallel.SometimesTwo lines in intersecting planes are ? skew.SometimesSkew lines are ? coplanar.NeverSkew lines ? intersect.NeverOpposite rays ? form a line.AlwaysParallel planes ? intersect.NeverThree points are ? coplanar.AlwaysIf two planes intersect, then their intersections is ? a plane.NeverThe intersection of two planes is ? a line.AlwaysIntersecting lines are ? parallel.NeverRay LG and TG are ? opposite rays?NeverComplementary and Supplementary Angles are ? adjacent?Sometimes

Answer from: Quest

$4\left(625^4\right)\left(y^6\right)$

step-by-step explanation:

given expression is $4\sqrt{625^8y^{12}}$ .

now we need to simplify the given expression $\sqrt{20y^8}$ .

we know that square root is equivalent to the power 1/2. so that means we can take half of the exponents to get the square root of given expression.

$4\sqrt{625^8y^{12}}$

$=4\left(625^8y^{12}\right)^{\frac{1}{2}}$

$=4\left(625^8\right)^{\frac{1}{2}}\left(y^{12}\right)^{\frac{1}{2}}$

$=4\left(625^4\right)\left(y^6\right)$

expanding that will give a very very large number so let's keep answer in exponent form.

Answer from: Quest

step-by-step explanation:

hihi so drawing these 2 triangles is fairly simple. all that's left is finding the height of each one. luckily, we have a side length and an angle, so there is a trig function we can use to solve for the height. the easiest one to use would be tangent, since we have 2/3 things needed to find and the third needed is what we are solving for. tan(73°) * 30 ~= 98.13 and tan(73°) * 35 ~= 114.45

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Which of the following statements are never true? select all that apply. three points are coplanar...