Which of the following equations have only one solution? select all correct answers. 4x 2 + 4x = 0 x 2 + 6x + 9 = 0 9x 2 - 25 = 0 5x 2 + 20x + 20 = 0 x 2 - x - 6 = 0

2nd and 4th equation will have only one solution.

Step-by-step explanation:

1). 4x² + 4x = 0

4x(x + 1) = 0

x = 0

or (x + 1) = 0 ⇒ x = -1

2). x² + 6x + 9 = 0

(x + 3)² = 0

(x + 3) = 0

x = -3

3). 9x² - 25 = 0

9x² = 25

x² =

x = ±

x = ±

4). 5x² + 20x + 20 = 0

5(x² + 4x + 4) = 0

(x + 2)²= 0

x + 2 = 0

x = -2

5). x² - x - 6 = 0

x² - 3x + 2x - 6 = 0

x(x - 3) + 2(x - 3) = 0

(x + 2)(x - 3) = 0

x = -2 or x = 3

Therefore, 2nd and 4th equations have only one solution.

what’s the question?

income. 10x+1300

expenses 3x+(1800+1500)

expenses 3x+3300

to break even:

income = expense,

10x + 1300 = 3x + 3300,

solve for x.

step-by-step explanation:

mark brainliest