Selma's class is making care packages to give to victims of a natural disaster. selma packs one box in 5 minutes and has already packed 12 boxes. her friend trudy packs one box in 7 minutes and has already packed 18 boxes. how many more minutes does each need to work in order to have packed the same number of boxes?

Selma      Trudy

12 + x/5 = 18 + x/7    (x = amount of time, in minutes)

x/5 - x/7 = 18 - 12

7x/35-5x/35=6

35*6/2=105 minutes

%282x%29%2F35%29%29 = 6  >  x = %2835%2A6%29%2F2 = 105 minutes.

Answer.  105 minutes,  or 1 hour and 45 minutes.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.