What is the measure of the vertex angle of an isosceles triangle if one of its base angles measures 73° and its congruent sides each measure 15 cm?

The measure of the vertex angle will be 34°

Step-by-step explanation:

As isosceles triangle have two equals sides and two equals angle. The two equals angle are the base angles b. We know that the sum of the angle of a triangle is 180°:

v+b+b=180°

v+2b=180°

Where v is the vertex angle. If we know the value of the base angles is 73° then the remaing vertex angle will be calculated by solving for a in the equation above:

v=180°-2*73°

v=180°-146°=34°

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