What are the zeros of the function? what are their multiplicities? y=(x-2)(x+7)^3

1)2) x=2, multiplicity 1 x=-7, multiplicity is 3.

Step-by-step explanation:

1) The zeros of this function are the roots of it. Which number added to -2 will return 0 for the first factor (x-2)? Similarly, which one added to -7 for the second factor (x+7)³ will return 0?

2) The multiplicity of a function is the number of repeated times, a factor  of a polynomial function appears in its factored form. So,

The factor is (x+7) whose multiplicity is 3, then x=-7, multiplicity=3

The factor (x-2), then x=2, multiplicity =1

true

step-by-step explanation:

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1^3 + 2^3 + 3^3 +4^3 = (1+2+3+4)^2

step-by-step explanation:

i am only able to answer the first part. i am not sure about the second part. sorry