Abcd is a parallelogram. e is the point where the diagonals ac and bd meet. prove that triangle abe is congruent to triangle cde

Step-by-step explanation:

Given that ABCD is  a parallelogram.

E is the point where the diagonals AC and BD meet.

Consider triangles ABE and CDE

Statement                         Reason

1) AB =CD                         Opposite sides of a parallelogram

2) Angle ABE =

Angle EDC                      Alternate angles of two parallel lines

3) BE = DE                       Diagonals bisect each other in a parallelogram

Hence by SAS axiom the two triangles are congruent.

i am unable to solve this problem

step-by-step explanation:

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2