The time a basketball player spends in the air when shooting a basket is called the "hang time." the vertical leap l measured in feet is related to the hang time t measured in seconds by the equation lequals=4 t squared4t2. suppose that a basketball player has a vertical leap of 33 feet 88 inches. find the hang time for this leap

0.957 seconds. The numbers in this problem don't look sane. I assume that the correct leap is 3 feet 8 inches. Not 33 feet 88 inches. One reason for this assumption is that the world record for a high jump is just a fraction of an inch over 8 feet. First, let's convert that height value to a decimal value of feet. 3 + 8/12 = 3 + 0.66667 = 3.66667 Now take the equation and solve for t, then substitute the known values and calculate. L = 4t^2 L/4 = t^2 sqrt(L/4) = t sqrt(3.66667/4) = t sqrt(0.9166675) = t 0.957427543 = t So the hang time for the leap mentioned is 0.957 seconds.

Will show energy on x axis time on the y axis feel free to ask any questions