Find the matrix aa representing the reflection about the line ll in r2r2 which consists of all scalar multiples of the vector [45][45].

 All scalar multiples of the vector [ 4, 5] makes the line y = 5/4 x. 

The matrix A of the orthogonal projection onto the line L is made of the coordinates of the projections of the base trajectories i and j onto the line L printed in columns. 

The line L: y = 5/4*x 

Orthogonal line passing over the point (1, 0): y = -4/5 *x + 4/5

Point of Intersection: (16/41, 21/41) 

Projections: P(i) = 16/41 i + 21/41 j, P(j) = 16/41 i + 21/41 j 

The matrix: 

A = || 16/41..16/41|| 
|| 16/4116/41 ||

answer

d. 10

explanation

the distance from point y to wx is the height of the triangle.

using pythagoras theorem,

group similar terms to get,

this implies that,

take positive square root of both sides to get,

this implies that,

on a coordinate grid, point a is at (−4.0, −2.4) and point b is at (4.0, −2.4). point b is a reflection of point a across the –axis. input either a lowercase x or i think is the right awnser

step-by-step explanation: