Me, i have no idea what the equation for the new path is.

First, find the slope of the initial line; 

m=(y₁-y₂)/(x₁-x₂) 

m=(4-0)/(11-8) 
m=4/3 

If two lines are parallel, the slope is the same although the intercept can differ. 

If this parallel lines passes through the point (4, 5); 

y=(4/3)x+c <-- plug in coordinates to solve for c
5=(4/3)(4)+c 
(15/3)=16/3+c 
(15/3)-(16/3)=c 
-1/3=c 

Therefore, the final equation should be y=4/3x-1/3

Hope I Helped :)