Astudent invested $5000 in two different savings accounts. the first account pays an annula interest rate of 3%. the second account pays an annual interest rate 4% at the end of the year, she earned $185 in interest. how much money did she invest in each account

solution

You use this formula to get the amount invested in each account

Let the amount invested in the first account be p, then the amount invested in the second account is $5000-p

This gives us

P(1.03)+($5000-p)1.04=$5000+$185

1.03p+$5200-1.04p=$5185

$5200-$5185=0.01p

$15=0.01p

P=$15/0.01

P=$1,500

Therefore

In the first account the student invested amount $1,500 and in the second account, the student invested amount $3500

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation:

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.