The vertices of a triangle are p(-4,1), q(-2,-8), and r(8,-1). what are the vertices of the image reflected across the y-axis?

An image reflected over the x axis is in the same position on the x axis, but the opposite position on the y axis. So if you had a line at (2,2) to (4,5) and you reflected it over the x axis it would be at (2,-2) to (4, -5) 

Now apply this to our problem..

P(-4, 1) > P(-4, -1)
Q(-2, -8) > Q(-2, 8)
R(8, -1) > R(8, 1)

Hope this helps!

Answer: 10pi

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

We need the pictures of the graphs