What is the equation in point-slope form of a line that passes through the points (7, −8) and (−4, 6) ? y+6=−1411(x−4) y−6=−1411(x+4) y+6=−23(x−4) y−6=−23(x+4)

Y-6=-14/11(x+4)
The slope is (6+8)/(-4-7), by the equation y1-y2/x1-x2. This equals -14/11. 
In point slope, you follow the form y-y1=m(x-x1) where m is the slope, and x1 and y1 are two points on the coordinate plane. If you substitute in (-4,6), you get the second answer choice, y-6=-14/11(x+4)