Sin(θ) = − 9/41 where 3π/2 < θ < 2π how to find sin(2θ) sin(θ/2) cos(2θ) cos(θ/2) tan(2θ) tan(θ/2)

We know the angle 3π/2 < θ < 2π  that simply means that θ is the IV quadrant, where the sine is negative, and the cosine is positive,

now, we know the sine is -9/41.... which is the negative?  well, the hypotenuse, the denominator, is never negative because is just a radius unit, so the negative has to be the numerator of 9.



now, we know what the sine and cosine are for θ, let's use that then,