If you roll a fair six-sided dice twice, what is the probability of getting a 2 and a 3, in no particular order

You want to find out the probability of getting a 2 first and getting a 3 on a fair dice; 

P(rolling 2 and 3)= (1/6)(1/6) <-- knowing that rolling a 2 has a possibility of 1/6, same with rolling a 3. 

Therefore, the probability of getting a 2 and a three or 3 and a two is 1/36

Hope I helped :)