At the animal shelter there are 56 more dogs than cats. if the total number of animals is 200 how many of each type are in the shelter? set up and solve the problem following the steps below: a).define the unknown quantities in terms of one variable

At the animal shelter there are 56 more dogs than cats. If the total number of animals is 200 how many of each type are in the shelter?

dogs + cats = 200        eq I 
dogs = 56 + cats         eq II

replace dogs in eq I

(56 + cats) + cats = 200 eq with one variable

56 + 2c = 200 
2c = 200 - 56 
2c = 144 /divided 2

cats= 72

dogs = 56 + cats = 56 + 72 = 128

dogs = 126

7.666270253x10 raised to the 18th power

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph

there is a hike in both the graphs so the graphs are increasing on their domain.x-intercept of log x and log 6x are differentthere is a vertical asymptote of both the graphs so there is no y-interceptas both the graphs are increasing so there is no horizontal asymptote